1+3(3v-2)=-2(2v-5)+4v

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Solution for 1+3(3v-2)=-2(2v-5)+4v equation:


Simplifying
1 + 3(3v + -2) = -2(2v + -5) + 4v

Reorder the terms:
1 + 3(-2 + 3v) = -2(2v + -5) + 4v
1 + (-2 * 3 + 3v * 3) = -2(2v + -5) + 4v
1 + (-6 + 9v) = -2(2v + -5) + 4v

Combine like terms: 1 + -6 = -5
-5 + 9v = -2(2v + -5) + 4v

Reorder the terms:
-5 + 9v = -2(-5 + 2v) + 4v
-5 + 9v = (-5 * -2 + 2v * -2) + 4v
-5 + 9v = (10 + -4v) + 4v

Combine like terms: -4v + 4v = 0
-5 + 9v = 10 + 0
-5 + 9v = 10

Solving
-5 + 9v = 10

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 9v = 10 + 5

Combine like terms: -5 + 5 = 0
0 + 9v = 10 + 5
9v = 10 + 5

Combine like terms: 10 + 5 = 15
9v = 15

Divide each side by '9'.
v = 1.666666667

Simplifying
v = 1.666666667

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