1+3(2n-1)=2(4n-2)

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Solution for 1+3(2n-1)=2(4n-2) equation: 



1+3(2n-1)=2(4n-2)

We move all terms to the left:

1+3(2n-1)-(2(4n-2))=0

We multiply parentheses

6n-(2(4n-2))-3+1=0



We calculate terms in parentheses: -(2(4n-2)), so:

2(4n-2)

We multiply parentheses

8n-4

Back to the equation:

-(8n-4)



We add all the numbers together, and all the variables

6n-(8n-4)-2=0

We get rid of parentheses

6n-8n+4-2=0

We add all the numbers together, and all the variables

-2n+2=0

We move all terms containing n to the left, all other terms to the right

-2n=-2

n=-2/-2

n=1

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