1+3(-5+4z)=6z-2

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Solution for 1+3(-5+4z)=6z-2 equation: 



1+3(-5+4z)=6z-2

We move all terms to the left:

1+3(-5+4z)-(6z-2)=0

We add all the numbers together, and all the variables

3(4z-5)-(6z-2)+1=0

We multiply parentheses

12z-(6z-2)-15+1=0

We get rid of parentheses

12z-6z+2-15+1=0

We add all the numbers together, and all the variables

6z-12=0

We move all terms containing z to the left, all other terms to the right

6z=12

z=12/6

z=2

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