1+2*(ln(x))-x=0

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Solution for 1+2*(ln(x))-x=0 equation:


Simplifying
1 + 2(ln(x)) + -1x = 0

Multiply ln * x
1 + 2(lnx) + -1x = 0

Solving
1 + 2lnx + -1x = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 2lnx + -1 + -1x = 0 + -1

Reorder the terms:
1 + -1 + 2lnx + -1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2lnx + -1x = 0 + -1
2lnx + -1x = 0 + -1

Combine like terms: 0 + -1 = -1
2lnx + -1x = -1

Add 'x' to each side of the equation.
2lnx + -1x + x = -1 + x

Combine like terms: -1x + x = 0
2lnx + 0 = -1 + x
2lnx = -1 + x

Divide each side by '2nx'.
l = -0.5n-1x-1 + 0.5n-1

Simplifying
l = -0.5n-1x-1 + 0.5n-1

Reorder the terms:
l = 0.5n-1 + -0.5n-1x-1

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