1+2(b+6)=4(b-1)

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Solution for 1+2(b+6)=4(b-1) equation: 



1+2(b+6)=4(b-1)

We move all terms to the left:

1+2(b+6)-(4(b-1))=0

We multiply parentheses

2b-(4(b-1))+12+1=0



We calculate terms in parentheses: -(4(b-1)), so:

4(b-1)

We multiply parentheses

4b-4

Back to the equation:

-(4b-4)



We add all the numbers together, and all the variables

2b-(4b-4)+13=0

We get rid of parentheses

2b-4b+4+13=0

We add all the numbers together, and all the variables

-2b+17=0

We move all terms containing b to the left, all other terms to the right

-2b=-17

b=-17/-2

b=8+1/2

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