1+2(a+1)=3(a+14)

Solution for 1+2(a+1)=3(a+14) equation:

1+2(a+1)=3(a+14)

We move all terms to the left:

1+2(a+1)-(3(a+14))=0

We multiply parentheses

2a-(3(a+14))+2+1=0


We calculate terms in parentheses: -(3(a+14)), so:

3(a+14)

We multiply parentheses

3a+42

Back to the equation:

-(3a+42)


We add all the numbers together, and all the variables

2a-(3a+42)+3=0

We get rid of parentheses

2a-3a-42+3=0

We add all the numbers together, and all the variables

-1a-39=0

We move all terms containing a to the left, all other terms to the right

-a=39

a=39/-1

a=-39