1+2(6-x)=2x-3(4x+1)

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Solution for 1+2(6-x)=2x-3(4x+1) equation: 



1+2(6-x)=2x-3(4x+1)

We move all terms to the left:

1+2(6-x)-(2x-3(4x+1))=0

We add all the numbers together, and all the variables

2(-1x+6)-(2x-3(4x+1))+1=0

We multiply parentheses

-2x-(2x-3(4x+1))+12+1=0



We calculate terms in parentheses: -(2x-3(4x+1)), so:

2x-3(4x+1)

We multiply parentheses

2x-12x-3

We add all the numbers together, and all the variables

-10x-3

Back to the equation:

-(-10x-3)



We add all the numbers together, and all the variables

-2x-(-10x-3)+13=0

We get rid of parentheses

-2x+10x+3+13=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2

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