1+2(-4v-)=-(-3+2v)-6v

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Solution for 1+2(-4v-)=-(-3+2v)-6v equation:



1+2(-4v-)=-(-3+2v)-6v
We move all terms to the left:
1+2(-4v-)-(-(-3+2v)-6v)=0
We add all the numbers together, and all the variables
2(-4v)-(-(2v-3)-6v)+1=0
We multiply parentheses
-8v-(-(2v-3)-6v)+1=0
We calculate terms in parentheses: -(-(2v-3)-6v), so:
-(2v-3)-6v
We add all the numbers together, and all the variables
-6v-(2v-3)
We get rid of parentheses
-6v-2v+3
We add all the numbers together, and all the variables
-8v+3
Back to the equation:
-(-8v+3)
We get rid of parentheses
-8v+8v-3+1=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation

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