1+12(1-2x)=8+11(1-2x)

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Solution for 1+12(1-2x)=8+11(1-2x) equation: 



1+12(1-2x)=8+11(1-2x)

We move all terms to the left:

1+12(1-2x)-(8+11(1-2x))=0

We add all the numbers together, and all the variables

12(-2x+1)-(8+11(-2x+1))+1=0

We multiply parentheses

-24x-(8+11(-2x+1))+12+1=0



We calculate terms in parentheses: -(8+11(-2x+1)), so:

8+11(-2x+1)

determiningTheFunctionDomain
11(-2x+1)+8

We multiply parentheses

-22x+11+8

We add all the numbers together, and all the variables

-22x+19

Back to the equation:

-(-22x+19)



We add all the numbers together, and all the variables

-24x-(-22x+19)+13=0

We get rid of parentheses

-24x+22x-19+13=0

We add all the numbers together, and all the variables

-2x-6=0

We move all terms containing x to the left, all other terms to the right

-2x=6

x=6/-2

x=-3

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