1+11y=7+3(9+y)

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Solution for 1+11y=7+3(9+y) equation: 



1+11y=7+3(9+y)

We move all terms to the left:

1+11y-(7+3(9+y))=0

We add all the numbers together, and all the variables

11y-(7+3(y+9))+1=0



We calculate terms in parentheses: -(7+3(y+9)), so:

7+3(y+9)

determiningTheFunctionDomain
3(y+9)+7

We multiply parentheses

3y+27+7

We add all the numbers together, and all the variables

3y+34

Back to the equation:

-(3y+34)



We get rid of parentheses

11y-3y-34+1=0

We add all the numbers together, and all the variables

8y-33=0

We move all terms containing y to the left, all other terms to the right

8y=33

y=33/8

y=4+1/8

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