1+1+2(d+1)=3+8(b+9)

Solution for 1+1+2(d+1)=3+8(b+9) equation:

Simplifying
1 + 1 + 2(d + 1) = 3 + 8(b + 9)

Reorder the terms:
1 + 1 + 2(1 + d) = 3 + 8(b + 9)
1 + 1 + (1 * 2 + d * 2) = 3 + 8(b + 9)
1 + 1 + (2 + 2d) = 3 + 8(b + 9)

Combine like terms: 1 + 1 = 2
2 + 2 + 2d = 3 + 8(b + 9)

Combine like terms: 2 + 2 = 4
4 + 2d = 3 + 8(b + 9)

Reorder the terms:
4 + 2d = 3 + 8(9 + b)
4 + 2d = 3 + (9 * 8 + b * 8)
4 + 2d = 3 + (72 + 8b)

Combine like terms: 3 + 72 = 75
4 + 2d = 75 + 8b

Solving
4 + 2d = 75 + 8b

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 2d = 75 + -4 + 8b

Combine like terms: 4 + -4 = 0
0 + 2d = 75 + -4 + 8b
2d = 75 + -4 + 8b

Combine like terms: 75 + -4 = 71
2d = 71 + 8b

Divide each side by '2'.
d = 35.5 + 4b

Simplifying
d = 35.5 + 4b