1+0.4(x-2)=3/5x

Solution for 1+0.4(x-2)=3/5x equation:

1+0.4(x-2)=3/5x

We move all terms to the left:

1+0.4(x-2)-(3/5x)=0


Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

0.4(x-2)-(+3/5x)+1=0

We multiply parentheses

0.4x-(+3/5x)-0.8+1=0

We get rid of parentheses

0.4x-3/5x-0.8+1=0

We multiply all the terms by the denominator


(0.4x)*5x-(0.8)*5x+1*5x-3=0

We add all the numbers together, and all the variables

(+0.4x)*5x-(0.8)*5x+1*5x-3=0

We multiply parentheses

0x^2-4x+1*5x-3=0

Wy multiply elements

0x^2-4x+5x-3=0

We add all the numbers together, and all the variables

x^2+x-3=0

a = 1; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·1·(-3)
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{13}}{2*1}=\frac{-1-\sqrt{13}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{13}}{2*1}=\frac{-1+\sqrt{13}}{2}
$