1+(7z/2)=z+6

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Solution for 1+(7z/2)=z+6 equation: 



1+(7z/2)=z+6

We move all terms to the left:

1+(7z/2)-(z+6)=0

We add all the numbers together, and all the variables

(+7z/2)-(z+6)+1=0

We get rid of parentheses

7z/2-z-6+1=0

We multiply all the terms by the denominator


7z-z*2-6*2+1*2=0

We add all the numbers together, and all the variables

7z-z*2-10=0

Wy multiply elements

7z-2z-10=0

We add all the numbers together, and all the variables

5z-10=0

We move all terms containing z to the left, all other terms to the right

5z=10

z=10/5

z=2

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