1+(3x+40)+(5x-10)=90

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Solution for 1+(3x+40)+(5x-10)=90 equation: 



1+(3x+40)+(5x-10)=90

We move all terms to the left:

1+(3x+40)+(5x-10)-(90)=0

We add all the numbers together, and all the variables

(3x+40)+(5x-10)-89=0

We get rid of parentheses

3x+5x+40-10-89=0

We add all the numbers together, and all the variables

8x-59=0

We move all terms containing x to the left, all other terms to the right

8x=59

x=59/8

x=7+3/8

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