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1+(2x-6)=-3+2(x-1)
We move all terms to the left:
1+(2x-6)-(-3+2(x-1))=0
We get rid of parentheses
2x-(-3+2(x-1))-6+1=0
We calculate terms in parentheses: -(-3+2(x-1)), so:We add all the numbers together, and all the variables
-3+2(x-1)
determiningTheFunctionDomain 2(x-1)-3
We multiply parentheses
2x-2-3
We add all the numbers together, and all the variables
2x-5
Back to the equation:
-(2x-5)
2x-(2x-5)-5=0
We get rid of parentheses
2x-2x+5-5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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