1+(2/x)=x/(x+3)

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Solution for 1+(2/x)=x/(x+3) equation: 


D( x )

x = 0

x+3 = 0

x = 0

x = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:0) U (0:+oo)

2/x+1 = x/(x+3) // - x/(x+3)

2/x-(x/(x+3))+1 = 0

(-1*x)/(x+3)+2/x+1 = 0

(-1*x^2)/(x*(x+3))+(2*(x+3))/(x*(x+3))+(1*x*(x+3))/(x*(x+3)) = 0

2*(x+3)+1*x*(x+3)-1*x^2 = 0

x^2-x^2+2*x+3*x+6 = 0

5*x+6 = 0

(5*x+6)/(x*(x+3)) = 0

(5*x+6)/(x*(x+3)) = 0 // * x*(x+3)

5*x+6 = 0

5*x+6 = 0 // - 6

5*x = -6 // : 5

x = -6/5

x = -6/5

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