1+(1/n)=(1/7n)

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Solution for 1+(1/n)=(1/7n) equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

1/n+1 = (1/7)*n // - (1/7)*n

1/n-((1/7)*n)+1 = 0

(-1/7)*n+1/n+1 = 0

1*n^-1-1/7*n^1+1*n^0 = 0

(1*n^1-1/7*n^2+1*n^0)/(n^1) = 0 // * n^2

n^1*(1*n^1-1/7*n^2+1*n^0) = 0

n^1

(-1/7)*n^2+n+1 = 0

(-1/7)*n^2+n+1 = 0

DELTA = 1^2-(1*4*(-1/7))

DELTA = 11/7

DELTA > 0

n = ((11/7)^(1/2)-1)/(2*(-1/7)) or n = (-(11/7)^(1/2)-1)/(2*(-1/7))

n = -7/2*((11/7)^(1/2)-1) or n = 7/2*((11/7)^(1/2)+1)

n in { -7/2*((11/7)^(1/2)-1), 7/2*((11/7)^(1/2)+1)} 

n in { -7/2*((11/7)^(1/2)-1), 7/2*((11/7)^(1/2)+1) }

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