1(y+4)=2(y+-8)+-10

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Solution for 1(y+4)=2(y+-8)+-10 equation: 


Simplifying
1(y + 4) = 2(y + -8) + -10

Reorder the terms:
1(4 + y) = 2(y + -8) + -10
(4 * 1 + y * 1) = 2(y + -8) + -10
(4 + 1y) = 2(y + -8) + -10

Reorder the terms:
4 + 1y = 2(-8 + y) + -10
4 + 1y = (-8 * 2 + y * 2) + -10
4 + 1y = (-16 + 2y) + -10

Reorder the terms:
4 + 1y = -16 + -10 + 2y

Combine like terms: -16 + -10 = -26
4 + 1y = -26 + 2y

Solving
4 + 1y = -26 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
4 + 1y + -2y = -26 + 2y + -2y

Combine like terms: 1y + -2y = -1y
4 + -1y = -26 + 2y + -2y

Combine like terms: 2y + -2y = 0
4 + -1y = -26 + 0
4 + -1y = -26

Add '-4' to each side of the equation.
4 + -4 + -1y = -26 + -4

Combine like terms: 4 + -4 = 0
0 + -1y = -26 + -4
-1y = -26 + -4

Combine like terms: -26 + -4 = -30
-1y = -30

Divide each side by '-1'.
y = 30

Simplifying
y = 30

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