1(x-8)-3=3(x+4)

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Solution for 1(x-8)-3=3(x+4) equation: 



1(x-8)-3=3(x+4)

We move all terms to the left:

1(x-8)-3-(3(x+4))=0



We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

1(x-8)-3x-12-3=0

We add all the numbers together, and all the variables

-3x+1(x-8)-15=0

We move all terms containing x to the left, all other terms to the right

-3x+1(x-8)=15

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