1(x-1)=2(3x+1)

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Solution for 1(x-1)=2(3x+1) equation: 



1(x-1)=2(3x+1)

We move all terms to the left:

1(x-1)-(2(3x+1))=0



We calculate terms in parentheses: -(2(3x+1)), so:

2(3x+1)

We multiply parentheses

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

1(x-1)-6x-2=0

We add all the numbers together, and all the variables

-6x+1(x-1)-2=0

We move all terms containing x to the left, all other terms to the right

-6x+1(x-1)=2

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