1(x+4)-8=8(x-1)

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Solution for 1(x+4)-8=8(x-1) equation: 



1(x+4)-8=8(x-1)

We move all terms to the left:

1(x+4)-8-(8(x-1))=0



We calculate terms in parentheses: -(8(x-1)), so:

8(x-1)

We multiply parentheses

8x-8

Back to the equation:

-(8x-8)



We get rid of parentheses

1(x+4)-8x+8-8=0

We add all the numbers together, and all the variables

-8x+1(x+4)=0

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