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1(x+-3)+2x=-(x+-5)+4
We move all terms to the left:
1(x+-3)+2x-(-(x+-5)+4)=0
We add all the numbers together, and all the variables
1(x-3)+2x-(-(x-5)+4)=0
We add all the numbers together, and all the variables
2x+1(x-3)-(-(x-5)+4)=0
We calculate terms in parentheses: -(-(x-5)+4), so:We get rid of parentheses
-(x-5)+4
We get rid of parentheses
-x+5+4
We add all the numbers together, and all the variables
-1x+9
Back to the equation:
-(-1x+9)
2x+1(x-3)+1x-9=0
We add all the numbers together, and all the variables
3x+1(x-3)-9=0
We move all terms containing x to the left, all other terms to the right
3x+1(x-3)=9
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