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1(x)=2(3x-1)
We move all terms to the left:
1(x)-(2(3x-1))=0
We add all the numbers together, and all the variables
x-(2(3x-1))=0
We calculate terms in parentheses: -(2(3x-1)), so:We get rid of parentheses
2(3x-1)
We multiply parentheses
6x-2
Back to the equation:
-(6x-2)
x-6x+2=0
We add all the numbers together, and all the variables
-5x+2=0
We move all terms containing x to the left, all other terms to the right
-5x=-2
x=-2/-5
x=2/5
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