1(t+2)+1=8

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Solution for 1(t+2)+1=8 equation: 


Simplifying
1(t + 2) + 1 = 8

Reorder the terms:
1(2 + t) + 1 = 8
(2 * 1 + t * 1) + 1 = 8
(2 + 1t) + 1 = 8

Reorder the terms:
2 + 1 + 1t = 8

Combine like terms: 2 + 1 = 3
3 + 1t = 8

Solving
3 + 1t = 8

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 1t = 8 + -3

Combine like terms: 3 + -3 = 0
0 + 1t = 8 + -3
1t = 8 + -3

Combine like terms: 8 + -3 = 5
1t = 5

Divide each side by '1'.
t = 5

Simplifying
t = 5

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