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1(p-5)=(10+2p)
We move all terms to the left:
1(p-5)-((10+2p))=0
We add all the numbers together, and all the variables
1(p-5)-((2p+10))=0
We calculate terms in parentheses: -((2p+10)), so:We get rid of parentheses
(2p+10)
We get rid of parentheses
2p+10
Back to the equation:
-(2p+10)
1(p-5)-2p-10=0
We add all the numbers together, and all the variables
-2p+1(p-5)-10=0
We move all terms containing p to the left, all other terms to the right
-2p+1(p-5)=10
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