1(p)+4(1-p)=3(p)+(1-p)

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Solution for 1(p)+4(1-p)=3(p)+(1-p) equation: 



1(p)+4(1-p)=3(p)+(1-p)

We move all terms to the left:

1(p)+4(1-p)-(3(p)+(1-p))=0

We add all the numbers together, and all the variables

1p+4(-1p+1)-(3p+(-1p+1))=0

We add all the numbers together, and all the variables

p+4(-1p+1)-(3p+(-1p+1))=0

We multiply parentheses

p-4p-(3p+(-1p+1))+4=0



We calculate terms in parentheses: -(3p+(-1p+1)), so:

3p+(-1p+1)

We get rid of parentheses

3p-1p+1

We add all the numbers together, and all the variables

2p+1

Back to the equation:

-(2p+1)



We add all the numbers together, and all the variables

-3p-(2p+1)+4=0

We get rid of parentheses

-3p-2p-1+4=0

We add all the numbers together, and all the variables

-5p+3=0

We move all terms containing p to the left, all other terms to the right

-5p=-3

p=-3/-5

p=3/5

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