1(c+19)+(10c+3)=143

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Solution for 1(c+19)+(10c+3)=143 equation:


Simplifying
1(c + 19) + (10c + 3) = 143

Reorder the terms:
1(19 + c) + (10c + 3) = 143
(19 * 1 + c * 1) + (10c + 3) = 143
(19 + 1c) + (10c + 3) = 143

Reorder the terms:
19 + 1c + (3 + 10c) = 143

Remove parenthesis around (3 + 10c)
19 + 1c + 3 + 10c = 143

Reorder the terms:
19 + 3 + 1c + 10c = 143

Combine like terms: 19 + 3 = 22
22 + 1c + 10c = 143

Combine like terms: 1c + 10c = 11c
22 + 11c = 143

Solving
22 + 11c = 143

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-22' to each side of the equation.
22 + -22 + 11c = 143 + -22

Combine like terms: 22 + -22 = 0
0 + 11c = 143 + -22
11c = 143 + -22

Combine like terms: 143 + -22 = 121
11c = 121

Divide each side by '11'.
c = 11

Simplifying
c = 11

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