1(7x-3)=7(-3x+5)+2

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Solution for 1(7x-3)=7(-3x+5)+2 equation:



1(7x-3)=7(-3x+5)+2
We move all terms to the left:
1(7x-3)-(7(-3x+5)+2)=0
We calculate terms in parentheses: -(7(-3x+5)+2), so:
7(-3x+5)+2
We multiply parentheses
-21x+35+2
We add all the numbers together, and all the variables
-21x+37
Back to the equation:
-(-21x+37)
We get rid of parentheses
1(7x-3)+21x-37=0
We add all the numbers together, and all the variables
21x+1(7x-3)-37=0
We move all terms containing x to the left, all other terms to the right
21x+1(7x-3)=37

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