1(6x+3)=2(4x+5)

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Solution for 1(6x+3)=2(4x+5) equation: 



1(6x+3)=2(4x+5)

We move all terms to the left:

1(6x+3)-(2(4x+5))=0



We calculate terms in parentheses: -(2(4x+5)), so:

2(4x+5)

We multiply parentheses

8x+10

Back to the equation:

-(8x+10)



We get rid of parentheses

1(6x+3)-8x-10=0

We add all the numbers together, and all the variables

-8x+1(6x+3)-10=0

We move all terms containing x to the left, all other terms to the right

-8x+1(6x+3)=10

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