1(4z-1)=3(z+2)

Solution for 1(4z-1)=3(z+2) equation:

Simplifying
1(4z + -1) = 3(z + 2)

Reorder the terms:
1(-1 + 4z) = 3(z + 2)
(-1 * 1 + 4z * 1) = 3(z + 2)
(-1 + 4z) = 3(z + 2)

Reorder the terms:
-1 + 4z = 3(2 + z)
-1 + 4z = (2 * 3 + z * 3)
-1 + 4z = (6 + 3z)

Solving
-1 + 4z = 6 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-1 + 4z + -3z = 6 + 3z + -3z

Combine like terms: 4z + -3z = 1z
-1 + 1z = 6 + 3z + -3z

Combine like terms: 3z + -3z = 0
-1 + 1z = 6 + 0
-1 + 1z = 6

Add '1' to each side of the equation.
-1 + 1 + 1z = 6 + 1

Combine like terms: -1 + 1 = 0
0 + 1z = 6 + 1
1z = 6 + 1

Combine like terms: 6 + 1 = 7
1z = 7

Divide each side by '1'.
z = 7

Simplifying
z = 7