1(4x+36)2=(3x-3)

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Solution for 1(4x+36)2=(3x-3) equation: 



1(4x+36)2=(3x-3)

We move all terms to the left:

1(4x+36)2-((3x-3))=0

We multiply parentheses

8x-((3x-3))+72=0



We calculate terms in parentheses: -((3x-3)), so:

(3x-3)

We get rid of parentheses

3x-3

Back to the equation:

-(3x-3)



We get rid of parentheses

8x-3x+3+72=0

We add all the numbers together, and all the variables

5x+75=0

We move all terms containing x to the left, all other terms to the right

5x=-75

x=-75/5

x=-15

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