1(34+-3y)+3y=34

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Solution for 1(34+-3y)+3y=34 equation: 


Simplifying
1(34 + -3y) + 3y = 34
(34 * 1 + -3y * 1) + 3y = 34
(34 + -3y) + 3y = 34

Combine like terms: -3y + 3y = 0
34 + 0 = 34
34 = 34

Add '-34' to each side of the equation.
34 + -34 = 34 + -34

Combine like terms: 34 + -34 = 0
0 = 34 + -34

Combine like terms: 34 + -34 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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