1(2x+1)=7(1x+5)

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Solution for 1(2x+1)=7(1x+5) equation: 



1(2x+1)=7(1x+5)

We move all terms to the left:

1(2x+1)-(7(1x+5))=0

We add all the numbers together, and all the variables

1(2x+1)-(7(x+5))=0



We calculate terms in parentheses: -(7(x+5)), so:

7(x+5)

We multiply parentheses

7x+35

Back to the equation:

-(7x+35)



We get rid of parentheses

1(2x+1)-7x-35=0

We add all the numbers together, and all the variables

-7x+1(2x+1)-35=0

We move all terms containing x to the left, all other terms to the right

-7x+1(2x+1)=35

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