1(20-2x)=2(3x-10)

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Solution for 1(20-2x)=2(3x-10) equation: 



1(20-2x)=2(3x-10)

We move all terms to the left:

1(20-2x)-(2(3x-10))=0

We add all the numbers together, and all the variables

1(-2x+20)-(2(3x-10))=0



We calculate terms in parentheses: -(2(3x-10)), so:

2(3x-10)

We multiply parentheses

6x-20

Back to the equation:

-(6x-20)



We get rid of parentheses

1(-2x+20)-6x+20=0

We add all the numbers together, and all the variables

-6x+1(-2x+20)+20=0

We move all terms containing x to the left, all other terms to the right

-6x+1(-2x+20)=-20

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