1(12z+3)-6=-4(-3z+4)+14

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Solution for 1(12z+3)-6=-4(-3z+4)+14 equation:


Simplifying
1(12z + 3) + -6 = -4(-3z + 4) + 14

Reorder the terms:
1(3 + 12z) + -6 = -4(-3z + 4) + 14
(3 * 1 + 12z * 1) + -6 = -4(-3z + 4) + 14
(3 + 12z) + -6 = -4(-3z + 4) + 14

Reorder the terms:
3 + -6 + 12z = -4(-3z + 4) + 14

Combine like terms: 3 + -6 = -3
-3 + 12z = -4(-3z + 4) + 14

Reorder the terms:
-3 + 12z = -4(4 + -3z) + 14
-3 + 12z = (4 * -4 + -3z * -4) + 14
-3 + 12z = (-16 + 12z) + 14

Reorder the terms:
-3 + 12z = -16 + 14 + 12z

Combine like terms: -16 + 14 = -2
-3 + 12z = -2 + 12z

Add '-12z' to each side of the equation.
-3 + 12z + -12z = -2 + 12z + -12z

Combine like terms: 12z + -12z = 0
-3 + 0 = -2 + 12z + -12z
-3 = -2 + 12z + -12z

Combine like terms: 12z + -12z = 0
-3 = -2 + 0
-3 = -2

Solving
-3 = -2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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