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1(10x+4)=2(3x-4)
We move all terms to the left:
1(10x+4)-(2(3x-4))=0
We calculate terms in parentheses: -(2(3x-4)), so:We get rid of parentheses
2(3x-4)
We multiply parentheses
6x-8
Back to the equation:
-(6x-8)
1(10x+4)-6x+8=0
We add all the numbers together, and all the variables
-6x+1(10x+4)+8=0
We move all terms containing x to the left, all other terms to the right
-6x+1(10x+4)=-8
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