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1(1+2/3x)=11/15
We move all terms to the left:
1(1+2/3x)-(11/15)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1(2/3x+1)-(+11/15)=0
We get rid of parentheses
1(2/3x+1)-11/15=0
We calculate fractions
()/3x+(-33x)/3x=0
We multiply all the terms by the denominator
(-33x)+()=0
We add all the numbers together, and all the variables
(-33x)=0
We get rid of parentheses
-33x=0
x=0/-33
x=0
Równanie nie ma rozwiązania
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