1(-x-2)+-4(x-3)=20

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Solution for 1(-x-2)+-4(x-3)=20 equation:


Simplifying
1(-1x + -2) + -4(x + -3) = 20

Reorder the terms:
1(-2 + -1x) + -4(x + -3) = 20
(-2 * 1 + -1x * 1) + -4(x + -3) = 20
(-2 + -1x) + -4(x + -3) = 20

Reorder the terms:
-2 + -1x + -4(-3 + x) = 20
-2 + -1x + (-3 * -4 + x * -4) = 20
-2 + -1x + (12 + -4x) = 20

Reorder the terms:
-2 + 12 + -1x + -4x = 20

Combine like terms: -2 + 12 = 10
10 + -1x + -4x = 20

Combine like terms: -1x + -4x = -5x
10 + -5x = 20

Solving
10 + -5x = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -5x = 20 + -10

Combine like terms: 10 + -10 = 0
0 + -5x = 20 + -10
-5x = 20 + -10

Combine like terms: 20 + -10 = 10
-5x = 10

Divide each side by '-5'.
x = -2

Simplifying
x = -2

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