0=y2+1.0515y-0.5893

Solution for 0=y2+1.0515y-0.5893 equation:

0=y2+1.0515y-0.5893

We move all terms to the left:

0-(y2+1.0515y-0.5893)=0

We add all the numbers together, and all the variables

-(+y^2+1.0515y-0.5893)+0=0

We add all the numbers together, and all the variables

-(+y^2+1.0515y-0.5893)=0

We get rid of parentheses

-y^2-1.0515y+0.5893=0

We add all the numbers together, and all the variables

-1y^2-1.0515y+0.5893=0

a = -1; b = -1.0515; c = +0.5893;
Δ = b2-4ac
Δ = -1.05152-4·(-1)·0.5893
Δ = 3.46285225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.0515)-\sqrt{3.46285225}}{2*-1}=\frac{1.0515-\sqrt{3.46285225}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.0515)+\sqrt{3.46285225}}{2*-1}=\frac{1.0515+\sqrt{3.46285225}}{-2}
$