0=y(12y-12)

Solution for 0=y(12y-12) equation:

0=y(12y-12)

We move all terms to the left:

0-(y(12y-12))=0

We add all the numbers together, and all the variables

-(y(12y-12))=0


We calculate terms in parentheses: -(y(12y-12)), so:

y(12y-12)

We multiply parentheses

12y^2-12y

Back to the equation:

-(12y^2-12y)


We get rid of parentheses

-12y^2+12y=0

a = -12; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-12)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-12}=\frac{-24}{-24}
=1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-12}=\frac{0}{-24}
=0
$