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0=x2+15x-19
We move all terms to the left:
0-(x2+15x-19)=0
We add all the numbers together, and all the variables
-(+x^2+15x-19)+0=0
We add all the numbers together, and all the variables
-(+x^2+15x-19)=0
We get rid of parentheses
-x^2-15x+19=0
We add all the numbers together, and all the variables
-1x^2-15x+19=0
a = -1; b = -15; c = +19;
Δ = b2-4ac
Δ = -152-4·(-1)·19
Δ = 301
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{301}}{2*-1}=\frac{15-\sqrt{301}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{301}}{2*-1}=\frac{15+\sqrt{301}}{-2} $
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