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0=x2+11x
We move all terms to the left:
0-(x2+11x)=0
We add all the numbers together, and all the variables
-(+x^2+11x)+0=0
We add all the numbers together, and all the variables
-(+x^2+11x)=0
We get rid of parentheses
-x^2-11x=0
We add all the numbers together, and all the variables
-1x^2-11x=0
a = -1; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·(-1)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*-1}=\frac{0}{-2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*-1}=\frac{22}{-2} =-11 $
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