0=x-3/8x-5

Solution for 0=x-3/8x-5 equation:

0=x-3/8x-5

We move all terms to the left:

0-(x-3/8x-5)=0


Domain of the equation: 8x-5)!=0

x∈R


We add all the numbers together, and all the variables

-(x-3/8x-5)=0

We get rid of parentheses

-x+3/8x+5=0

We multiply all the terms by the denominator


-x*8x+5*8x+3=0

Wy multiply elements

-8x^2+40x+3=0

a = -8; b = 40; c = +3;
Δ = b2-4ac
Δ = 402-4·(-8)·3
Δ = 1696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1696}=\sqrt{16*106}=\sqrt{16}*\sqrt{106}=4\sqrt{106}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-4\sqrt{106}}{2*-8}=\frac{-40-4\sqrt{106}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+4\sqrt{106}}{2*-8}=\frac{-40+4\sqrt{106}}{-16}
$