0=x(125-12x)

Solution for 0=x(125-12x) equation:

0=x(125-12x)

We move all terms to the left:

0-(x(125-12x))=0

We add all the numbers together, and all the variables

-(x(-12x+125))+0=0

We add all the numbers together, and all the variables

-(x(-12x+125))=0


We calculate terms in parentheses: -(x(-12x+125)), so:

x(-12x+125)

We multiply parentheses

-12x^2+125x

Back to the equation:

-(-12x^2+125x)


We get rid of parentheses

12x^2-125x=0

a = 12; b = -125; c = 0;
Δ = b2-4ac
Δ = -1252-4·12·0
Δ = 15625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15625}=125$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-125)-125}{2*12}=\frac{0}{24}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-125)+125}{2*12}=\frac{250}{24}
=10+5/12
$