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0=x(-0.6x+4)
We move all terms to the left:
0-(x(-0.6x+4))=0
We add all the numbers together, and all the variables
-(x(-0.6x+4))=0
We calculate terms in parentheses: -(x(-0.6x+4)), so:We get rid of parentheses
x(-0.6x+4)
We multiply parentheses
0x^2+4x
We add all the numbers together, and all the variables
x^2+4x
Back to the equation:
-(x^2+4x)
-x^2-4x=0
We add all the numbers together, and all the variables
-1x^2-4x=0
a = -1; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·(-1)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*-1}=\frac{0}{-2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*-1}=\frac{8}{-2} =-4 $
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