0=x(-0.005x+1)

Solution for 0=x(-0.005x+1) equation:

0=x(-0.005x+1)

We move all terms to the left:

0-(x(-0.005x+1))=0

We add all the numbers together, and all the variables

-(x(-0.005x+1))=0


We calculate terms in parentheses: -(x(-0.005x+1)), so:

x(-0.005x+1)

We multiply parentheses

0x^2+x

We add all the numbers together, and all the variables

x^2+x

Back to the equation:

-(x^2+x)


We get rid of parentheses

-x^2-x=0

We add all the numbers together, and all the variables

-1x^2-1x=0

a = -1; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-1)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-1}=\frac{0}{-2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-1}=\frac{2}{-2}
=-1
$