0=t(32-15t)

Solution for 0=t(32-15t) equation:

0=t(32-15t)

We move all terms to the left:

0-(t(32-15t))=0

We add all the numbers together, and all the variables

-(t(-15t+32))+0=0

We add all the numbers together, and all the variables

-(t(-15t+32))=0


We calculate terms in parentheses: -(t(-15t+32)), so:

t(-15t+32)

We multiply parentheses

-15t^2+32t

Back to the equation:

-(-15t^2+32t)


We get rid of parentheses

15t^2-32t=0

a = 15; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·15·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*15}=\frac{0}{30}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*15}=\frac{64}{30}
=2+2/15
$