0=t(3.85-4.905t)

Solution for 0=t(3.85-4.905t) equation:

0=t(3.85-4.905t)

We move all terms to the left:

0-(t(3.85-4.905t))=0

We add all the numbers together, and all the variables

-(t(-4.905t+3.85))+0=0

We add all the numbers together, and all the variables

-(t(-4.905t+3.85))=0


We calculate terms in parentheses: -(t(-4.905t+3.85)), so:

t(-4.905t+3.85)

We multiply parentheses

-4t^2+3.85t

Back to the equation:

-(-4t^2+3.85t)


We get rid of parentheses

4t^2-3.85t=0

a = 4; b = -3.85; c = 0;
Δ = b2-4ac
Δ = -3.852-4·4·0
Δ = 14.8225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.85)-\sqrt{14.8225}}{2*4}=\frac{3.85-\sqrt{14.8225}}{8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.85)+\sqrt{14.8225}}{2*4}=\frac{3.85+\sqrt{14.8225}}{8}
$