0=t(-2.4-0.8t)

Solution for 0=t(-2.4-0.8t) equation:

0=t(-2.4-0.8t)

We move all terms to the left:

0-(t(-2.4-0.8t))=0

We add all the numbers together, and all the variables

-(t(-0.8t-2.4))+0=0

We add all the numbers together, and all the variables

-(t(-0.8t-2.4))=0


We calculate terms in parentheses: -(t(-0.8t-2.4)), so:

t(-0.8t-2.4)

We multiply parentheses

0t^2-2.4t

We add all the numbers together, and all the variables

t^2-2.4t

Back to the equation:

-(t^2-2.4t)


We get rid of parentheses

-t^2+2.4t=0

We add all the numbers together, and all the variables

-1t^2+2.4t=0

a = -1; b = 2.4; c = 0;
Δ = b2-4ac
Δ = 2.42-4·(-1)·0
Δ = 5.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-\sqrt{5.76}}{2*-1}=\frac{-2.4-\sqrt{5.76}}{-2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+\sqrt{5.76}}{2*-1}=\frac{-2.4+\sqrt{5.76}}{-2}
$