0=ln(x+2)-x+1

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Solution for 0=ln(x+2)-x+1 equation:


Simplifying
0 = ln(x + 2) + -1x + 1

Reorder the terms:
0 = ln(2 + x) + -1x + 1
0 = (2 * ln + x * ln) + -1x + 1
0 = (2ln + lnx) + -1x + 1

Reorder the terms:
0 = 1 + 2ln + lnx + -1x

Solving
0 = 1 + 2ln + lnx + -1x

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-2ln' to each side of the equation.
0 + -2ln = 1 + 2ln + lnx + -2ln + -1x
Remove the zero:
-2ln = 1 + 2ln + lnx + -2ln + -1x

Reorder the terms:
-2ln = 1 + 2ln + -2ln + lnx + -1x

Combine like terms: 2ln + -2ln = 0
-2ln = 1 + 0 + lnx + -1x
-2ln = 1 + lnx + -1x

Add '-1lnx' to each side of the equation.
-2ln + -1lnx = 1 + lnx + -1lnx + -1x

Combine like terms: lnx + -1lnx = 0
-2ln + -1lnx = 1 + 0 + -1x
-2ln + -1lnx = 1 + -1x

Reorder the terms:
-1 + -2ln + -1lnx + x = 1 + -1x + -1 + x

Reorder the terms:
-1 + -2ln + -1lnx + x = 1 + -1 + -1x + x

Combine like terms: 1 + -1 = 0
-1 + -2ln + -1lnx + x = 0 + -1x + x
-1 + -2ln + -1lnx + x = -1x + x

Combine like terms: -1x + x = 0
-1 + -2ln + -1lnx + x = 0

The solution to this equation could not be determined.

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